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James Linley in Florida

2 people named James Linley have been found in our database in Florida, including in cities like Fort Lauderdale and Pompano Beach. Get access to their date of birth, home addresses, phone numbers, email addresses, workplaces, social profiles, and more.
Description

James Linley was born on July 19, 1951. He is now 73 years old. Based on public records, this person has 2 family members. Linley lived at 6 different addresses in 5 cities. The present address is 1670 23rd Ave, Fort Lauderdale, Florida, 33312. The phone numbers associated with James Linley are (954) 791-0585 and (954) 551-0627. Also, there are 2 email addresses that belong to James.

Address History
1670 23rd Ave, Fort Lauderdale, FL, 33312 Current
87455 Old Hwy, Islamorada, FL, 33036 2012 – 2017
516 Industrial Dr, Lewisberry, PA, 17339 2007
Phone Number History
(954) 791-0585 (954) 551-0627
Description

901 River Dr, Pompano Beach, Florida, 33063 is Linley’s address. Previously, he resided at 1 other address in 2 cities. According to our records, James Linley’s phone number is (954) 540-8431.

Address History
901 River Dr, Pompano Beach, FL, 33063 Current
901 River Dr, Margate, FL, 33063 2014 – 2016
Phone Number History
(954) 540-8431

FAQ about James Linley

Born on July 19, 1951, James Linley has already turned or will soon turn 73.

You can try to reach James Linley via phone at (954) 791-0585. We have additional 3 phone numbers for James Linley.

You can try to reach out to James Linley at the following email addresses: [email protected] or [email protected]

Since 1994, James Linley has been living at 1670 23rd Ave, Fort Lauderdale, Florida, 33312.

Previously, James Linley lived at 87455 Old Hwy, Islamorada, Florida, 33036 · 516 Industrial Dr, Lewisberry, Pennsylvania, 17339 · 2655 Le Jeune Rd, Miami, Florida, 33134.

The following people are believed to be James Linley's family: Beatriz Linley, John Linley.

The following nicknames are associated with James Linley’s name and be be referred to he: Yakub Linley, Yaqoob Linley, Yaqub Linley.